Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 15 - Multiple Integrals - Review - Exercises - Page 1074: 5

Answer

$\frac{1}{2}sin(1)$

Work Step by Step

$\int_{0}^{1}\int_{0}^{x}cos(x^{2})dydx=\int_{0}^{1}ycos(x^{2})|_{0}^{x}dx$ $=\int_{0}^{1}xcos(x^{2})dx$ $=\frac{1}{2}sin(x^{2})|_{0}^{1}$ $=\frac{1}{2}sin(1)$
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