Answer
$$\frac{\partial{f}}{\partial{x}}=-3y,\quad\frac{\partial{f}}{\partial{y}}=5y^{4}-3x$$
Work Step by Step
$$f(x,y)=y^{5}-3xy$$
$$\frac{\partial{f}}{\partial{x}}=-3y,\quad\frac{\partial{f}}{\partial{y}}=5y^{4}-3x$$
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