Chapter 13 - Vector Functions - 13.4 Exercises - Page 895: 43

$4.5 cm/s^2,9.0 cm/s^2$

From the given figure:$\theta= 63.5^\circ$ Thus, Tangential component of $a$ : $a_T=10 \cos \theta =10 \cos (63.5^\circ)\approx 4.5 cm/s^2$ and Normal component of $a$ : $a_N=10 \sin \theta =10 \sin (63.5^\circ) \approx 9.0 cm/s^2$