Answer
(a) $4x^2-8x+2$
(b) $2x^2+4x-5$
(c) $8x-21$
Work Step by Step
$f(x) = x^2+2x-1$
$g(x) = 2x-3$
(a) $f \circ g$
$ = (2x-3)^2+2(2x-3)-1$
$ = 4x^2-12x+9+4x-6-1$
$ = 4x^2-8x+2$
(b) $g \circ f$
$ = 2(x^2+2x-1)-3$
$ = 2x^2+4x-2-3$
$ = 2x^2+4x-5$
(c) $g \circ g$
$= 2(2x-3)-3$
$= 4x-9$
$g\circ g \circ g$
$= 2(4x-9)-3$
$= 8x-21$
