Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.8 - The Derivative as a Function - 2.8 Exercises - Page 162: 35

Answer

(a) $U'(t)$ is the rate of change of the percentage of unemployed and it is measured in units of percentage per year. (b) We can estimate the values for $U'(t)$: 2003: $U'(t) = -0.50$ 2004: $U'(t) = -0.45$ 2005: $U'(t) = -0.45$ 2006: $U'(t) = -0.25$ 2007: $U'(t) = 0.60$ 2008: $U'(t) = 2.35$ 2009: $U'(t) = 1.90$ 2010: $U'(t) = -0.20$ 2011: $U'(t) = -0.75$ 2012: $U'(t) = -0.80$

Work Step by Step

(a) $U'(t)$ is the rate of change of the percentage of unemployed and it is measured in units of percentage per year. (b) We can estimate the values for $U'(t)$: 2003: $U'(t) = \frac{5.5-6.0}{1} = -0.50$ 2004: $U'(t) = \frac{5.1-6.0}{2} = -0.45$ 2005: $U'(t) = \frac{4.6-5.5}{2} = -0.45$ 2006: $U'(t) = \frac{4.6-5.1}{2} = -0.25$ 2007: $U'(t) = \frac{5.8-4.6}{2} = 0.60$ 2008: $U'(t) = \frac{9.3-4.6}{2} = 2.35$ 2009: $U'(t) = \frac{9.6-5.8}{2} = 1.90$ 2010: $U'(t) = \frac{8.9-9.3}{2} = -0.20$ 2011: $U'(t) = \frac{8.1-9.6}{2} = -0.75$ 2012: $U'(t) = \frac{8.1-8.9}{1} = -0.80$
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