Answer
We can see a graph of $f'(x)$ below the graph of $f(x)$
Work Step by Step
We can see a graph of $f'(x)$ below the graph of $f(x)$
Note that the slope is undefined where the graph of $f(x)$ has a sharp point at $x=0$
Also note that $f'(x)$ is symmetric about the origin because $f'(-x) = -f'(x)$