Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 10 - Review - Exercises - Page 690: 4



Work Step by Step

$x=2cos\theta$ $y=1+sin\theta$ $cos^2\theta=\frac{x^2}{4}$ $sin^2\theta =(y-1)^2$ Therefore, $cos^2\theta+sin^2\theta=\frac{x^2}{4}+(y-1)^2$ $\frac{x^2}{4}+(y-1)^2=1$ Also see attached graph
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