Answer
See the graph
Work Step by Step
$f(x)=|x^2-4|x|+3|$
Therefore,
If $x\geq0$,
$f(x)=|x^2-4x+3|$
If $x\lt0$,
$f(x)=|x^2+4x+3|$
Graph these functions on their respective domains. To do so, sketch the quadratic inside the absolute value signs, then reflect all points with negative y-values over the x-axis.
