Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 13 - Multiple Integration - 13.2 Double Integrals over General Regions - 13.2 Exercises - Page 983: 77

Answer

\[A=1\]

Work Step by Step

\[\begin{align} & \text{From the graph} \\ & R=\left\{ \left( x,y \right):0\le y\le {{e}^{x}},\text{ }0\le x\le \ln 2\text{ } \right\} \\ & \text{Then,} \\ & A=\int_{0}^{\ln 2}{\int_{0}^{{{e}^{x}}}{dy}dx} \\ & \text{Integrate} \\ & A=\int_{0}^{\ln 2}{\left[ y \right]_{0}^{{{e}^{x}}}dx} \\ & A=\int_{0}^{\ln }{\left( {{e}^{x}}-0 \right)dx} \\ & A=\int_{0}^{\ln 2}{{{e}^{x}}dx} \\ & A=\left[ {{e}^{x}} \right]_{0}^{\ln 2} \\ & A={{e}^{\ln 2}}-{{e}^{0}} \\ & A=2-1 \\ & A=1 \\ \end{align}\]
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