Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Appendix A - Appendix A Exercises - Page 1157: 4

Answer

$$ - 1 \leqslant x \leqslant 5$$

Work Step by Step

$$\eqalign{ & \left| {x - 2} \right| \leqslant 3 \cr & {\text{Using the property }}\,\,\left| x \right| \leqslant a\,\, \Leftrightarrow \,\,\, - a \leqslant x \leqslant a \cr & {\text{We can write }}\left| {x - 2} \right| \leqslant 3{\text{ as:}} \cr & \left| {x - 2} \right| \leqslant 3\,\,\, \Leftrightarrow \,\, - 3 \leqslant x - 2 \leqslant 3 \cr & {\text{simplifying}} \cr & \left| {x - 2} \right| \leqslant 3\,\,\, \Leftrightarrow \,\, - 3 + 2 \leqslant x \leqslant 3 + 2 \cr & \left| {x - 2} \right| \leqslant 3\,\,\, \Leftrightarrow \,\,\,\,\,\,\,\,\,\,\, - 1 \leqslant x \leqslant 5 \cr} $$
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