Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - Review - Exercises - Page 198: 64


$$f'(x) = bx^ax^{b-1}g'(x^b)+ax^{a-1}g(x^b)$$

Work Step by Step

Given $$f (x)= x^ag(x^b) $$ Then \begin{align*} f'(x)&= x^ag'(x^b)(bx^{b-1}) + ax^{a-1}g(x^b) \\ &= bx^ax^{b-1}g'(x^b)+ax^{a-1}g(x^b) \end{align*}
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