Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - Review - Exercises - Page 197: 41

Answer

$$f''(2)= \frac{-4 }{27}$$

Work Step by Step

Given $$f(t)= \sqrt{4t+1}$$ Since \begin{align*} f'(t)&=\frac{4}{2\sqrt{4t+1}}=2(4t+1)^{-1/2}\\ f''(t)&=-4(4t+1)^{-3/2} \end{align*} then $$f''(2)=-4(4(2)+1)^{-3/2}=\frac{-4 }{27}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.