Answer
TRUE
Work Step by Step
By linearity of differentiation, $(y_{1}+y_{2})''=y_{1}''+y_{2}''$, so $(y_{1}+y_{2})''+(y_{1}+y_{2})=(y_{1}''+y_{1})+(y_{2}''+y_{2})=0+0=0$.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 17 - Second-Order Differential Equations - Review - True-False Quiz - Page 1221: 1
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