Chapter 8 - Techniques of Integration - 8.7 Improper Integrals - Preliminary Questions - Page 440: 1

a) the integral is improper because one of the limits of integration is infinite. Because the power of x in the intergrand is less than -1, this integral converges b) the integral is improper because intergrand is undefined at x = 0. Because the power of x in the integrand is less than -1, this integral diverges c) the integral is improper because one of the limits of integration is infinite. Because the power of x in the intergrand is greater than -1, this integral diverges c) the integral is improper because intergrand is undefined at x = 0. Because the power of x in the integrand is greater than -1, this integral converges

a) the integral is improper because one of the limits of integration is infinite. Because the power of x in the intergrand is less than -1, this integral converges b) the integral is improper because intergrand is undefined at x = 0. Because the power of x in the integrand is less than -1, this integral diverges c) the integral is improper because one of the limits of integration is infinite. Because the power of x in the intergrand is greater than -1, this integral diverges c) the integral is improper because intergrand is undefined at x = 0. Because the power of x in the integrand is greater than -1, this integral converges