Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.6 Net Change as the Integral of a Rate of Change - Exercises - Page 268: 15

Answer

$9200$ cars

Work Step by Step

= $\int_0^2(3000+2000t-300t^{2})dt$ = $(3000t-1000t^{2}-100t^{3})|_0^2$ = $(3000\times2)+(1000\times4)-(100\times8)$ = $9200$ cars
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