Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.2 Vectors in Three Dimensions - Exercises - Page 658: 6


$$\langle 4, 0, 1\rangle.$$

Work Step by Step

$$\overrightarrow{ PQ}=Q-P=(1,-4,3)-(-3,-4,2)=\langle 4, 0, 1\rangle.$$
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