Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.3 Polar Coordinates - Exercises - Page 618: 18


$$r = 5\sec \theta$$

Work Step by Step

Given $$ x=5$$ Since $ y=r\sin\theta,\ \ x= r\cos\theta,\ \ r^2=x^2+y^2 $, then \begin{align*} x&=5\\ r\cos\theta&=5 \\ r&= 5\sec \theta \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.