Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.3 Exercises - Page 126: 67

Answer

The equation of the tangent is $y=2x+\frac{2-\pi}{2}$

Work Step by Step

$f'(x)=\dfrac{d}{dx}\tan{x}=\sec^2{x}$. $f'(\frac{\pi}{4})=\sec^2{\frac{\pi}{4}}=2$. Equation of tangent: $(y-y_0)=m(x-x_0)$ at point $(x_0, y_0)$ and slope $m$. $(y-1)=2(x-\frac{\pi}{4})\rightarrow y=2x+\frac{2-\pi}{2}$. A graphing calculator and a computer algebra system have been used to confirm these results.
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