Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 15 - Vector Analysis - 15.6 Exercises - Page 1104: 1

Answer

$12\sqrt 2$

Work Step by Step

$S: z=4-x$ $dS=\sqrt 2$ Substitute $z=4-x$ (x,y) $\approx$D D is the projection of the surface on the xy plane $\sqrt 2[4][4(3)-(3)^2]$ $12\sqrt 2$
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