Answer
This surface is a plane.
Work Step by Step
\[
\begin{array}{l}
v+2 u=x \\
u-v=y \\
3 u=z
\end{array}
\]
Adding the two first equations, we get:
\[
x+y=2 u+v-(u-v)=3 u
\]
but $3 u=z$, so:
\[
x+y=z
\]
This surface is a plane.
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 14 - Multiple Integrals - 14.4 Surface Area; Parametric Surfaces - Exercises Set 14.4 - Page 1037: 27
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