Answer
$$f'(x)=g'(g(x))\times g'(x)$$
Work Step by Step
$f'(x)=\frac{d}{dx}g(g(x))$
Using the chain rule:
$f'(x)=\frac{dg(g(x))}{dg(x)}\times\frac{dg(x)}{dx}$
$=g'(g(x))\times g'(x)$
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