Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.2 - Proportion - Exercises - Page 278: 89

Answer

$30\;g$.

Work Step by Step

The given values are Base $B=300\;mL$. Rate $R=(1:10)100=10$. Let the pure silver nitrate is $P=x$. The formula is $\Rightarrow \frac{P}{B}=\frac{R}{100}$ Substitute all the values. $\Rightarrow \frac{x}{300\;mL}=\frac{10}{100}$ Cross multiply. $\Rightarrow 100x=3000\;mL$ Divide both sides by $100$. $\Rightarrow x=30\;mL$. Convert $mL$ to $g$. $\Rightarrow x=30\;mL\times \frac{1g}{1mL}$. Simplify. $\Rightarrow x=30\;g$.
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