Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.1 - Ratio - Exercises - Page 270: 29

Answer

50 mi/h

Work Step by Step

$\frac{625mi}{12\frac{1}{2}h}=\frac{625mi}{\frac{25}{2}h}=625\times\frac{2}{25}\ mi/h=\frac{1250}{25} mi/h=50 mi/h$
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