Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.7 - Formulas - Exercises - Page 255: 11

Answer

$$ h=\frac{v^2}{2g }.$$

Work Step by Step

To solve the given equation for $h$, we divide both sides by $2g $ as follows $$\frac{v^2}{2g }=\frac{2g h}{2g }\Longrightarrow h=\frac{v^2}{2g }.$$
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