Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 5 - Section 5.5 - Multiplication of Polynomials - Exercise - Page 226: 59

Answer

$10y^3 -24y^2 -32y+16$

Work Step by Step

We multiply each term of the first polynomial by each term of the second polynomial. Then we add the products, as follows $$ (2y^2 - 4y - 8)(5y - 2)= 2y^2 (5y - 2) - 4y (5y - 2) - 8(5y - 2)\\ = 10y^3 -4y^2-20y^2+8y-40y+16\\ =10y^3 -24y^2 -32y+16 .$$
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