Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Test - Page 209: 18

Answer

$0.01~m$, $0.005~m$, $0.00096$, $0.10\%$

Work Step by Step

For the measurement $5.20~m$, we have: The last digit is in the $0.01$ place, so the precision is $0.01~m$. The greatest possible error is one-half the precision: $0.5\cdot 0.01 \ rpm=0.005 \ m$ The relative error is $relative~error=\dfrac{greatest~possible~error}{measurement}$ $\frac{0.005\ m}{5.20\ m}=0.00096$ The percent of error is $0.096\%$.
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