Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.7 - Relative Error and Percent of Error - Exercise - Page 192: 23

Answer

$3\frac{5}{8} \ in, 3\frac{3}{8} \ in, \frac{1}{4} \ in$

Work Step by Step

The upper limit is the measurement + tolerance, that is, $$ 3\frac{1}{2}+\frac{1}{8}=3\frac{5}{8} \ in .$$ The lower limit is the measurement - tolerance, that is, $$ 3\frac{1}{2}-\frac{1}{8}=3\frac{3}{8} \ in .$$ The tolerance interval = upper limit - lower limit, that is, $$ 3\frac{5}{8}-3\frac{3}{8}=\frac{2}{8} \ in=\frac{1}{4} \ in .$$
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