Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Test - Page 134: 34

Answer

$$213\times 10^{18}$$

Work Step by Step

By adding the exponents and multiplying the like terms, we have $$(39.4\times 10^{6})(120\times 10^{-3})(45.0\times 10^{12})=212760\times 10^{15}\\ =213\times 10^{18}$$ which is in the engineering notation.
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