Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Cumulative Review - Page 134: 10

Answer

$$1\frac{7}{8}. $$

Work Step by Step

By unifying the denominators, we have $$ 6\frac{1}{2}-4\frac{5}{8}=\frac{13}{2}-\frac{37}{8}=\frac{52}{8}-\frac{37}{8}\\ =\frac{52-37}{8}=\frac{15}{8}=1\frac{7}{8}. $$
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