Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 15 - Section 15.2 - Circle Graphs - Exercise - Page 509: 3

Answer

$55^o$

Work Step by Step

We calculate $15.2\%$ of $360^{\circ}$ as follows: $$ \frac{15.2}{100}\times 360^o\approx 55^o .$$
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