Answer
$$ 89.4 \ in\ \ 411\ in^2.$$
Work Step by Step
The perimeter of the parallelogram is given by
$$2(23.9+20.8)=89.4 \ in.$$
The area is given by
$$ 23.9\times 17.2= 411.08\ in^2 \approx 411~in^2.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 12 - Section 12.2 - Quadrilaterals - Exercise - Page 391: 7
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