Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.6 - Factoring General Trinomials - Exercise - Page 356: 18

Answer

$(6a-5)(2a-3)$

Work Step by Step

For the polynomial $$ 12a^2 -28a +15 $$ we check the factors of $ac=12(15)=180$. The only factors that can give the right middle term are $-18$ and $-10$, as follows $$ 12a^2 -28a +15=(6a-5)(2a-3) .$$
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