Answer
See solution
Work Step by Step
$A=PBP^{-1}$
$A^2=(PBP^{-1})(PBP^{-1})=PB^2P^{-1}$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 5 - Eigenvalues and Eigenvectors - 5.4 Exercises - Page 296: 20
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