Answer
$\begin{bmatrix}
2&-4\\
-3&5
\end{bmatrix}$
Work Step by Step
$[T(\vec{d_1})_B\ \ \ \ T(\vec{d_2})_B\ \ \ T(\vec{d_3})_B ]=\begin{bmatrix}
2&-4\\
-3&5
\end{bmatrix}$
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