Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 3 - Section 3.4 - The Slope-Intercept Form of the Equation of a Line - Exercise Set - Page 252: 62

Answer

$$y = -x + 5$$

Work Step by Step

If the line in question has the same y-intercept as the line $2y = 6x + 8$, then if we transform this equation into the slope-intercept form, then we will have the y-intercept of the line we are looking for. If we divide both sides by $2$, then we have isolated $y$ to one side of the equation, and we also have the slope-intercept form of the equation: $$y = \frac{6}{2}x + \frac{8}{2}$$ Divide to simplify: $$y = 3x + 4$$ We see that the y-intercept for this line is $4$; therefore, the y-intercept of the line we are looking for is also $4$. The line that we are looking for is parallel to the line with equation $4x + 4y = 20$. If the lines are parallel, that means that they also share the same slope. Let's put this equation into the slope-intercept form as well to find the slope of this equation: We want $y$ on one side of the equation, so we want, first of all, to subtract $4x$ from each side of the equation: $$4y = -4x + 20$$ Now, to solve for $y$, we divide both sides by $4$: $$y = -x + 5$$ The slope of this line is $-1$, which means the line we are interested in also has a slope of $-1$. Now that we have the slope and y-intercept, we can set up the equation for the line that we are looking for: $$y = -x + 5$$
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