Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.4 - Division of Polynomials - Exercise Set - Page 445: 50

Answer

$3x^{2} -xy+2y^{2}$

Work Step by Step

$ \begin{array}{llllllllll} & & 3x^{2} & -xy & +2y^{2} & & & \color{red}{ \small{Quotient}} & & \\ & & -- & -- & -- & -- & -- & -- & & \\ 4x-5y & ) & 12x^{3} & -19x^{2}y & +13xy^{2} & -10y^{3} & & & & \\ & & 12x^{3} & -15x^{2}y & & & & \color{red}{\leftarrow \small{ 3x^{2}(4x-5y) } } & & \\ & & -- & -- & & & & \color{red}{\leftarrow \small{ subtract } } & & \\ & & & -4x^{2}y & +13xy^{2} & -10y^{3} & & & & \\ & & & -4x^{2}y & +5xy^{2} & & & \color{red}{\leftarrow \small{-xy(4x-5y) } } & & \\ & & & -- & -- & & & \color{red}{\leftarrow \small{ subtract }} & & \\ & & & & 8xy^{2} & -10y^{3} & & & & \\ & & & & 8xy^{2} & -10y^{3} & & \color{red}{\leftarrow \small{2y^{2}(4x-5y) } } & & \\ & & & & -- & -- & -- & \color{red}{\leftarrow \small{ subtract }} & & \\ & & & & & 0 & & \color{red}{\leftarrow \small{ Remainder } } & & \end{array}$ $\displaystyle \frac{12x^{3}-19x^{2}y+13xy^{2}-10y^{3}}{4x-5y}$ = $3x^{2} -xy+2y^{2}$
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