Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Test - Page 310: 2

Answer

$\frac{21}{8}\leq x$

Work Step by Step

$\frac{x}{6}+\frac{1}{8}\leq\frac{x}{2}-\frac{3}{4}$ I multiply the inequality by $24$, then: $4x+3\leq12x-18\\3\leq8x-18\\21\leq8x\\\frac{21}{8}\leq x$
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