Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 65: 6


$x=\dfrac{5200}{180}=\dfrac{260}{9}=28.89$ (approximate value)

Work Step by Step

Given that $\dfrac{80x}{100}+x=52$ We will have to isolate $x$. In order to this take whole terms other side to get the value of $x$. $100(\dfrac{80x}{100})+100x=5200$ or, $80x+100x=5200$ or, $180x=5200$ or, $x=\dfrac{5200}{180}=\dfrac{260}{9}=28.89$ (approximate value)
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