#### Answer

a. 8.4 million British pounds
b. 2003
c. (0,7.2) This means that in the year 2000, the prize money was 7.2 million British pounds
d. Domain = [3,10]; Range = [9,13]

#### Work Step by Step

a. $x=2002-2000=2$
Since x=2, the prize money (y) is ~ 8.4 million British pounds.
b. y=9 billion
Since y=9 billion, the year (x) is 3 years since 2000, so that would be $2000+3=2003$
c. This graph crosses the vertical axis (y-axis) at about 7.2, so the vertical intercept is $(0,7.2)$
d. Since this data seems pretty consistent, I will go one year before and one year after the data. This makes the domain = [3,10]. I will do the same thing with the range keeping to the same year spread as the domain. This makes the range = [9,13]