Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises: 76

Answer

x=$\frac{2y}{z^2}$

Work Step by Step

y=$\frac{1}{2}$xz$^2$ xz$^2$=2y x=$\frac{2y}{z^2}$
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