Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Appendix A - Basic Algebra Review - A Exercises - Page A-15: 93



Work Step by Step

Step 1: The exponent on $10$ is negative, so we divide $1.28$ by $10^{5}$. Step 2: This moves the decimal point $5$ places to the left, which means $1.28\times10^{-5}=0.0000128$.
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