Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Exercise Set - Page 440: 87b

Answer

$3$

Work Step by Step

Using the properties of radicals, the given expression, $ \sqrt{3}\cdot\sqrt{3} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt{3(3)} \\\\= \sqrt{(3)^2} \\\\= 3 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.