Answer
5 and 3 are solutions to the quadratic equation $x^2-8x+15=0$.
Work Step by Step
RECALL:
If $(x-a)(x-b)=0$, then $x=a$ and $x=b$ are solutions of the equation $(x-a)(x-b)=0$.
Since 5 and 3 are solutions of the quadratic equation, then the equation must be:
$(x-5)(x-3)=0$
Multiply the binomials to have:
$\\x(x-3) -5(x-3)=0
\\x^2-3x-5x-5(-3)=0
\\x^2-8x+15=0$
