Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Review - Page 332: 153

Answer

$$z^5(2z-7)(2z+7)$$

Work Step by Step

We have $$4z^7-49z^5$$ Factorizing $$z^5(4z^2-49)$$ $$z^5(2z-7)(2z+7)$$
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