Chapter 3 - Section 3.1 - Graphing Equations - Exercise Set - Page 126: 40

See graph

$y=x^2+3$ This is not a linear equation; this is a parabola. Substitute x-values to find their corresponding y-values. $y=(0)^2+3$ $y=3$ $(0,3)$ $y=(-1)^2+3$ $y=4$ $(-1,4)$ $y=(1)^2+3$ $y=4$ $(1,4)$ Plot these points and connect with a smooth curve.