Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Section 2.6 - Absolute Value Equations - Vocabulary, Readiness & Video Check - Page 100: 1

Answer

C

Work Step by Step

Solving equations with |X| = a where a is a positive number |X| = a is equivalent to X = a OR X = -a Given $|x - 2| = 5$ Since 5 is a positive number $x - 2 = 5$ OR $x - 2 = -5$
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