Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Section 1.3 - Operations on Real Numbers and Order of Operations - Exercise Set - Page 27: 45

Answer

$-\frac{2}{3}$

Work Step by Step

$-\sqrt \frac{4}{9}=-(\sqrt \frac{4}{9})=-(\frac{2}{3})=-\frac{2}{3}$ because $-(\frac{2}{3}^{2})=-(\frac{2}{3}\times\frac{2}{3})=-(\frac{4}{9})=-\frac{4}{9}$
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