Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Review: 123



Work Step by Step

Using order of operations, the expression $ \left( -\dfrac{2}{3} \right)^3\div\dfrac{10}{9} $ simplifies to \begin{array}{l} -\dfrac{8}{27}\cdot\dfrac{9}{10} \\\\= -\dfrac{2\cdot4}{9\cdot3}\cdot\dfrac{9}{2\cdot5} \\\\= -\dfrac{4}{3}\cdot\dfrac{1}{5} \\\\= -\dfrac{4}{15} .\end{array}
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