Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Test - Chapter R Test - Page 41: 22



Work Step by Step

We are given the expression $-3(2k-4)+4(3k-5)-2+4k$. We can use the distributive property to simplify the terms in parentheses and then combine like terms. $-3(2k-4)+4(3k-5)-2+4k=(-3\times2k)+(-3\times-4)+(4\times3k)+(4\times-5)-2+4k=(-6k)+(12)+(12k)+(-20)-2+4k=(-6+12+4)k+(12-20-2)=(10)k+(-10)=10k-10$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.