Answer
-1
Work Step by Step
For any positive real number $b$ (such that $b\ne1$), we know that $log_{b}b^{r}=r$ (as long as $r\gt0$).
For $log_{4}\frac{1}{4}$:
We know that $4^{-1}=\frac{1}{4}$, so we can replace $\frac{1}{4}$ with $4^{-1}$.
Therefore, $log_{4}\frac{1}{4}=log_{4}4^{-1}=-1$.
